Let \[f:[4,\infty )\to [1,\infty )\]be a function defined by \[f(x)={{5}^{x(x-4)}},\] then \[{{f}^{-1}}(x)\]is

\[{{\left( \frac{1}{5} \right)}^{x(x-4)}}\]

Let \[f:[4,\infty )\to [1,\infty )\]be a function defined by \[f(x)={{

1.	Let \[f:[4,\infty )\to [1,\infty )\]be a function defined by \[f(x)={{5}^{x(x-4)}},\] then \[{{f}^{-1}}(x)\]is
A.	\[2-\sqrt{4+{{\log }_{5}}x}\]
B.	\[2+\sqrt{4+{{\log }_{5}}x}\]
C.	\[{{\left( \frac{1}{5} \right)}^{x(x-4)}}\]
D.	None of these
Answer» C. \[{{\left( \frac{1}{5} \right)}^{x(x-4)}}\]

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Let \[f:[4,\infty )\to [1,\infty )\]be a function defined by \[f(x)={{5}^{x(x-4)}},\] then \[{{f}^{-1}}(x)\]is

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