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1. |
Let ϕ be the phase angle between the line current and line voltage, and α be the load angle. The per phase mechanical power developed by a synchronous motor is: |
A. | \(\frac{{{E_b}V}}{{{X_S}}}\sin \phi \) |
B. | \(\frac{{{E_b}V}}{{{X_S}}}\cos \alpha \) |
C. | \(\frac{{{E_b}V}}{{{X_s}}}\cos \phi \) |
D. | \(\frac{{{E_b}V}}{{{X_S}}}\sin \alpha \) |
Answer» E. | |