Let \(A = \left\{ {\theta \in \left( { - \frac{\pi }{2},{\rm{\;}}\pi } \right):\frac{{3 + 2i\;sin\theta }}{{1 - 2i\;sin\theta }}{\rm{\;is\;purely\;imaginary}}} \right\}\). Then the sum of elements in A is:

Let \(A = \left\{ {\theta \in \left( { - \frac{\pi }{2},{\rm{\;}}\pi }

1.	Let \(A = \left\{ {\theta \in \left( { - \frac{\pi }{2},{\rm{\;}}\pi } \right):\frac{{3 + 2i\;sin\theta }}{{1 - 2i\;sin\theta }}{\rm{\;is\;purely\;imaginary}}} \right\}\). Then the sum of elements in A is:
A.	\(\frac{{5\pi }}{6}\)
B.	π
C.	\(\frac{{3\pi }}{4}\)
D.	\(\frac{{2\pi }}{3}\)
Answer» E.