Let \[A=\left( \begin{matrix} 1 & -1 & 1 \\ 2 & 1 & -3 \\ 1 & 1 & 1 \\ \end{matrix} \right)\] and \[(10)B=\left( \begin{matrix} 4 & 2 & 2 \\ -5 & 0 & \alpha \\ 1 & -2 & 3 \\ \end{matrix} \right)\]. If B is the inverse of matrix A, then \[\alpha \]is [AIEEE 2004]

Let \[A=\left( \begin{matrix} 1 & -1 & 1 \\ 2 & 1 & -3 \\ 1 & 1 & 1

1.	Let \[A=\left( \begin{matrix} 1 & -1 & 1 \\ 2 & 1 & -3 \\ 1 & 1 & 1 \\ \end{matrix} \right)\] and \[(10)B=\left( \begin{matrix} 4 & 2 & 2 \\ -5 & 0 & \alpha \\ 1 & -2 & 3 \\ \end{matrix} \right)\]. If B is the inverse of matrix A, then \[\alpha \]is [AIEEE 2004]
A.	5
B.	-1
C.	2
D.	-2
Answer» B. -1

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Let \[A=\left( \begin{matrix} 1 & -1 & 1 \\ 2 & 1 & -3 \\ 1 & 1 & 1 \\ \end{matrix} \right)\] and \[(10)B=\left( \begin{matrix} 4 & 2 & 2 \\ -5 & 0 & \alpha \\ 1 & -2 & 3 \\ \end{matrix} \right)\]. If B is the inverse of matrix A, then \[\alpha \]is [AIEEE 2004]

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