Let \[a,b,c>0\] and \[x={{\tan }^{-1}}\sqrt{\frac{a}{bc}(a+b+c),}\] \[y={{\tan }^{-1}}\sqrt{\frac{b}{ca}(a+b+c)}\] and\[z={{\tan }^{-1}}\sqrt{\frac{c}{ab}(a+b+c)}\], then

Let \[a,b,c>0\] and \[x={{\tan }^{-1}}\sqrt{\frac{a}{bc}(a+b+c),}\] \[

1.	Let \[a,b,c>0\] and \[x={{\tan }^{-1}}\sqrt{\frac{a}{bc}(a+b+c),}\] \[y={{\tan }^{-1}}\sqrt{\frac{b}{ca}(a+b+c)}\] and\[z={{\tan }^{-1}}\sqrt{\frac{c}{ab}(a+b+c)}\], then
A.	\[\Sigma \tan x\tan y=1\]
B.	\[\Sigma \cot x\cot y=1\]
C.	\[\Sigma x=\frac{\pi }{2}\]
D.	None of these
Answer» C. \[\Sigma x=\frac{\pi }{2}\]

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Let \[a,b,c>0\] and \[x={{\tan }^{-1}}\sqrt{\frac{a}{bc}(a+b+c),}\] \[y={{\tan }^{-1}}\sqrt{\frac{b}{ca}(a+b+c)}\] and\[z={{\tan }^{-1}}\sqrt{\frac{c}{ab}(a+b+c)}\], then

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