Let A (1, 1, 1), B (2, 3, 5) and C (\[-\]1,0, 2) be three points, then equation of a plane parallel to the plane ABC which is at distance 2 is

Let A (1, 1, 1), B (2, 3, 5) and C (\[-\]1,0, 2) be three points, then

1.	Let A (1, 1, 1), B (2, 3, 5) and C (\[-\]1,0, 2) be three points, then equation of a plane parallel to the plane ABC which is at distance 2 is
A.	\[2x-3y+z+2\sqrt{14}=0\]
B.	\[2x-3y+z-\sqrt{14}=0\]
C.	\[2x-3y+z+2=0\]
D.	\[2x-3y+z-2=0\]
Answer» B. \[2x-3y+z-\sqrt{14}=0\]

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Let A (1, 1, 1), B (2, 3, 5) and C (\[-\]1,0, 2) be three points, then equation of a plane parallel to the plane ABC which is at distance 2 is

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