\({S_Y}\left( f \right) = \frac{1}{2}{S_X}\left( {\frac{f}{2}} \right){e^{ - j2\pi f}}\)

\({S_Y}\left( f \right) = \frac{1}{2}{S_X}\left( {\frac{f}{2}} \right){e^{ - j\pi f}}\)

\({S_Y}\left( f \right) = \frac{1}{2}{S_X}\left( {\frac{f}{2}} \right){e^{ - j\pi f/2}}\)

\({S_Y}\left( f \right) = \frac{1}{2}{S_X}\left( {\frac{f}{2}} \right)\)

Let ( – McqOptions

1.	Let (
A.	\({S_Y}\left( f \right) = \frac{1}{2}{S_X}\left( {\frac{f}{2}} \right){e^{ - j\pi f}}\)
B.	\({S_Y}\left( f \right) = \frac{1}{2}{S_X}\left( {\frac{f}{2}} \right){e^{ - j\pi f/2}}\)
C.	\({S_Y}\left( f \right) = \frac{1}{2}{S_X}\left( {\frac{f}{2}} \right)\)
D.	\({S_Y}\left( f \right) = \frac{1}{2}{S_X}\left( {\frac{f}{2}} \right){e^{ - j2\pi f}}\)
Answer» D. \({S_Y}\left( f \right) = \frac{1}{2}{S_X}\left( {\frac{f}{2}} \right){e^{ - j2\pi f}}\)

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