1.

Let \[0

A.        \[P(B/A)=P(B)-P(A)\]
B.        \[P({{A}^{c}}\cup {{B}^{c}})=P({{A}^{c}})+P({{B}^{c}})\]
C.        \[P{{(A\cup B)}^{c}}=P({{A}^{c}})\,P({{B}^{c}})\]
D.        \[P(A/B)=P(A)\]
Answer» D.        \[P(A/B)=P(A)\]


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