\[\left[ \sum\limits_{n=1}^{10}{\int\limits_{-2n-1}^{-2n}{{{\sin }^{27}}xdx}} \right]+\left[ \sum\limits_{n=1}^{10}{\int\limits_{2n}^{2n+1}{{{\sin }^{27}}}xdx} \right]=\]

\[\left[ \sum\limits_{n=1}^{10}{\int\limits_{-2n-1}^{-2n}{{{\sin }^{27

1.	\[\left[ \sum\limits_{n=1}^{10}{\int\limits_{-2n-1}^{-2n}{{{\sin }^{27}}xdx}} \right]+\left[ \sum\limits_{n=1}^{10}{\int\limits_{2n}^{2n+1}{{{\sin }^{27}}}xdx} \right]=\]
A.	\[{{27}^{2}}\]
B.	\[-54\]
C.	\[54\]
D.	0
Answer» E.

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\[\left[ \sum\limits_{n=1}^{10}{\int\limits_{-2n-1}^{-2n}{{{\sin }^{27}}xdx}} \right]+\left[ \sum\limits_{n=1}^{10}{\int\limits_{2n}^{2n+1}{{{\sin }^{27}}}xdx} \right]=\]

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