Left shifting an unsigned int or char by 1 is always equivalent to mul

1.	Left shifting an unsigned int or char by 1 is always equivalent to multiplying it by 2.
A.	1
B.
Answer» B.

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If an is 2 bytes wide then, What will be the output of the program ?
Left shifting an or by 1 is always equivalent to multiplying it by 2.
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Which of the following statements are correct about the program?_x000D_ #include<stdio.h>_x000D_ _x000D_ int main()_x000D_ {_x000D_ unsigned int m[] = {0x01, 0x02, 0x04, 0x08, 0x10, 0x20, 0x40, 0x80};_x000D_ unsigned char n, i;_x000D_ scanf("%d", &n);_x000D_ for(i=0; i<=7; i++)_x000D_ {_x000D_ if(n & m[i])_x000D_ printf("yes");_x000D_ }_x000D_ return 0;_x000D_ }
If an unsigned int is 2 bytes wide then, What will be the output of the program ?_x000D_ #include<stdio.h>_x000D_ _x000D_ int main()_x000D_ {_x000D_ unsigned int m = 32;_x000D_ printf("%x\n", ~m);_x000D_ return 0;_x000D_ }
What will be the output of the program ?_x000D_ #include<stdio.h>_x000D_ _x000D_ int main()_x000D_ {_x000D_ int i=4, j=8;_x000D_ printf("%d, %d, %d\n", i|j&j|i, i|j&&j|i, i^j);_x000D_ return 0;_x000D_ }
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What will be the output of the program? #include<stdio.h> int main() { printf("%d %d\n", 32<<1, 32<<0); printf("%d %d\n", 32<<-1, 32<<-0); printf("%d %d\n", 32>>1, 32>>0); printf("%d %d\n", 32>>-1, 32>>-0); return 0; }

Left shifting an unsigned int or char by 1 is always equivalent to multiplying it by 2.

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