$$\left[ {\frac{{\sqrt 3+ \sqrt 2 }}{{\sqrt 3- \sqrt 2 }} - \frac{{\sqrt 3- \sqrt 2 }}{{\sqrt 3+ \sqrt 2 }}} \right]$$simplifies to = ?

$$\left[ {\frac{{\sqrt 3+ \sqrt 2 }}{{\sqrt 3- \sqrt 2 }} - \frac{{\sq

1.	$$\left[ {\frac{{\sqrt 3+ \sqrt 2 }}{{\sqrt 3- \sqrt 2 }} - \frac{{\sqrt 3- \sqrt 2 }}{{\sqrt 3+ \sqrt 2 }}} \right]$$simplifies to = ?
A.	${\text{2}}\sqrt 6 $$
B.	${\text{4}}\sqrt 6 $$
C.	${\text{2}}\sqrt 3 $$
D.	${\text{3}}\sqrt 2 $$
Answer» C. ${\text{2}}\sqrt 3 $$