\[\left| \,\begin{matrix} a+b & b+c & c+a \\ b+c & c+a & a+b \\ c+a & a+b & b+c \\ \end{matrix}\, \right|=K\,\,\left| \,\begin{matrix} a & b & c \\ b & c & a \\ c & a & b \\ \end{matrix}\, \right|\,,\]then \[K=\] [EAMCET 1992; DCE 2000]

\[\left| \,\begin{matrix} a+b & b+c & c+a \\ b+c & c+a & a

1.	\[\left\| \,\begin{matrix} a+b & b+c & c+a \\ b+c & c+a & a+b \\ c+a & a+b & b+c \\ \end{matrix}\, \right\|=K\,\,\left\| \,\begin{matrix} a & b & c \\ b & c & a \\ c & a & b \\ \end{matrix}\, \right\|\,,\]then \[K=\] [EAMCET 1992; DCE 2000]
A.	1
B.	2
C.	3
D.	4
Answer» C. 3

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\[\left| \,\begin{matrix} a+b & b+c & c+a \\ b+c & c+a & a+b \\ c+a & a+b & b+c \\ \end{matrix}\, \right|=K\,\,\left| \,\begin{matrix} a & b & c \\ b & c & a \\ c & a & b \\ \end{matrix}\, \right|\,,\]then \[K=\] [EAMCET 1992; DCE 2000]

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