\[\left| \,\begin{matrix} a-1 & a & bc \\ b-1 & b & ca \\ c-1 & c & ab \\ \end{matrix}\, \right|=\] [RPET 1988]

\[{{a}^{3}}+{{b}^{3}}+{{c}^{3}}-3abc\]

\[\left| \,\begin{matrix} a-1 & a & bc \\ b-1 & b & ca \

1.	\[\left\| \,\begin{matrix} a-1 & a & bc \\ b-1 & b & ca \\ c-1 & c & ab \\ \end{matrix}\, \right\|=\] [RPET 1988]
A.	0
B.	\[(a-b)(b-c)(c-a)\]
C.	\[{{a}^{3}}+{{b}^{3}}+{{c}^{3}}-3abc\]
D.	None of these
Answer» E.

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\[\left| \,\begin{matrix} a-1 & a & bc \\ b-1 & b & ca \\ c-1 & c & ab \\ \end{matrix}\, \right|=\] [RPET 1988]

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