\[\left| \,\begin{matrix} 1 & a & {{a}^{2}}-bc \\ 1 & b & {{b}^{2}}-ac \\ 1 & c & {{c}^{2}}-ab \\ \end{matrix}\, \right|=\] [IIT 1988; MP PET 1990, 91; RPET 2002]

\[{{a}^{3}}+{{b}^{3}}+{{c}^{3}}-3abc\]

\[\left| \,\begin{matrix} 1 & a & {{a}^{2}}-bc \\ 1 & b &

1.	\[\left\| \,\begin{matrix} 1 & a & {{a}^{2}}-bc \\ 1 & b & {{b}^{2}}-ac \\ 1 & c & {{c}^{2}}-ab \\ \end{matrix}\, \right\|=\] [IIT 1988; MP PET 1990, 91; RPET 2002]
A.	0
B.	\[{{a}^{3}}+{{b}^{3}}+{{c}^{3}}-3abc\]
C.	\[3abc\]
D.	\[{{(a+b+c)}^{3}}\]
Answer» B. \[{{a}^{3}}+{{b}^{3}}+{{c}^{3}}-3abc\]

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\[\left| \,\begin{matrix} 1 & a & {{a}^{2}}-bc \\ 1 & b & {{b}^{2}}-ac \\ 1 & c & {{c}^{2}}-ab \\ \end{matrix}\, \right|=\] [IIT 1988; MP PET 1990, 91; RPET 2002]

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