\[\left( 1+\frac{1}{2\,!}+\frac{1}{4\,!}+.... \right)\,\,\left( 1+\frac{1}{3\,!}+\frac{1}{5\,!}+.... \right)\,=\]

\[\frac{{{e}^{4}}+1}{4\,{{e}^{2}}}\]

\[\frac{{{e}^{2}}-1}{{{e}^{2}}}\]

\[\frac{{{e}^{4}}-1}{4\,{{e}^{2}}}\]

\[\left( 1+\frac{1}{2\,!}+\frac{1}{4\,!}+.... \right)\,\,\left( 1+\fra

1.	\[\left( 1+\frac{1}{2\,!}+\frac{1}{4\,!}+.... \right)\,\,\left( 1+\frac{1}{3\,!}+\frac{1}{5\,!}+.... \right)\,=\]
A.	\[{{e}^{4}}\]
B.	\[\frac{{{e}^{2}}-1}{{{e}^{2}}}\]
C.	\[\frac{{{e}^{4}}-1}{4\,{{e}^{2}}}\]
D.	\[\frac{{{e}^{4}}+1}{4\,{{e}^{2}}}\]
Answer» D. \[\frac{{{e}^{4}}+1}{4\,{{e}^{2}}}\]

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\[\left( 1+\frac{1}{2\,!}+\frac{1}{4\,!}+.... \right)\,\,\left( 1+\frac{1}{3\,!}+\frac{1}{5\,!}+.... \right)\,=\]

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