MCQOPTIONS
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MCQOPTIONS
| 1. |
Last line of Lyman series for H-atom has wavelength \[{{\lambda }_{1}}\overset{o}{\mathop{A}}\,,\] \[{{2}^{nd}}\] line of Balmer series has wavelength \[{{\lambda }_{2}}\overset{o}{\mathop{A}}\,\] then |
| A. | \[\frac{16}{{{\lambda }_{1}}}=\frac{9}{{{\lambda }_{2}}}\] |
| B. | \[\frac{16}{{{\lambda }_{2}}}=\frac{9}{{{\lambda }_{1}}}\] |
| C. | \[\frac{4}{{{\lambda }_{1}}}=\frac{1}{{{\lambda }_{2}}}\] |
| D. | \[\frac{16}{{{\lambda }_{1}}}=\frac{3}{{{\lambda }_{2}}}\] |
| Answer» C. \[\frac{4}{{{\lambda }_{1}}}=\frac{1}{{{\lambda }_{2}}}\] | |