Laplace transform of the function f(t) is given by $F\left( s \right) = L\left\{ {f\left( t \right)} \right\} = \mathop \smallint \limits_0^\infty f\left( t \right){e^{ - st}}dt$. Laplace transform of the function shown below is given by

Question

TuteeHUB · Accepted Answer

$\frac{{1 - 2{e^{ - s}}}}{s}$

TuteeHUB · Answer

$\frac{{1 - {e^{ - 2s}}}}{s}$

TuteeHUB · Answer

$\frac{{1 - {e^{ - s}}}}{{2s}}$

TuteeHUB · Answer

$\frac{{2 - 2{e^{ - s}}}}{s}$

1.	Laplace transform of the function f(t) is given by \(F\left( s \right) = L\left\{ {f\left( t \right)} \right\} = \mathop \smallint \limits_0^\infty f\left( t \right){e^{ - st}}dt\). Laplace transform of the function shown below is given by
A.	\(\frac{{1 - {e^{ - 2s}}}}{s}\)
B.	\(\frac{{1 - {e^{ - s}}}}{{2s}}\)
C.	\(\frac{{2 - 2{e^{ - s}}}}{s}\)
D.	\(\frac{{1 - 2{e^{ - s}}}}{s}\)
Answer» D. \(\frac{{1 - 2{e^{ - s}}}}{s}\)

Laplace transform of the function f(t) is given by \(F\left( s \right) = L\left\{ {f\left( t \right)} \right\} = \mathop \smallint \limits_0^\infty f\left( t \right){e^{ - st}}dt\). Laplace transform of the function shown below is given by

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