Laplace transform of f(t) = t2 sin t is

Question

TuteeHUB · Accepted Answer

$\frac{{\left( {3{s^2} + 1} \right)}}{{{{\left( {{s^2} + 1} \right)}^3}}}$

TuteeHUB · Answer

$\frac{{3{s^2} - 1}}{{{{\left( {{s^2} + 1} \right)}^3}}}$

TuteeHUB · Answer

$\frac{{2\left( {3{s^2} - 1} \right)}}{{{{\left( {{s^2} + 1} \right)}^3}}}$

TuteeHUB · Answer

$\frac{{\left( {3{s^2} - 1} \right)}}{{{{\left( {{s^2} + 1} \right)}^3}}}$

1.	Laplace transform of f(t) = t2 sin t is
A.	\(\frac{{3{s^2} - 1}}{{{{\left( {{s^2} + 1} \right)}^3}}}\)
B.	\(\frac{{2\left( {3{s^2} - 1} \right)}}{{{{\left( {{s^2} + 1} \right)}^3}}}\)
C.	\(\frac{{\left( {3{s^2} + 1} \right)}}{{{{\left( {{s^2} + 1} \right)}^3}}}\)
D.	\(\frac{{\left( {3{s^2} - 1} \right)}}{{{{\left( {{s^2} + 1} \right)}^3}}}\)
Answer» C. \(\frac{{\left( {3{s^2} + 1} \right)}}{{{{\left( {{s^2} + 1} \right)}^3}}}\)

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