\[{{K}_{c}}\] for \[PC{{l}_{5}}(g)\rightleftharpoons PC{{l}_{3}}(g)+C{{l}_{2}}(g)\] is 0.04 at \[250{}^\circ C\]. How many moles of \[PC{{l}_{5}}\] must be added to a 3 L flask to obtain a \[C{{l}_{2}}\] concentration of 0.15M

\[{{K}_{c}}\] for \[PC{{l}_{5}}(g)\rightleftharpoons PC{{l}_{3}}(g)+C{

1.	\[{{K}_{c}}\] for \[PC{{l}_{5}}(g)\rightleftharpoons PC{{l}_{3}}(g)+C{{l}_{2}}(g)\] is 0.04 at \[250{}^\circ C\]. How many moles of \[PC{{l}_{5}}\] must be added to a 3 L flask to obtain a \[C{{l}_{2}}\] concentration of 0.15M
A.	4.2 moles
B.	2.1 moles
C.	5.5 moles
D.	6.3 moles
Answer» C. 5.5 moles

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\[{{K}_{c}}\] for \[PC{{l}_{5}}(g)\rightleftharpoons PC{{l}_{3}}(g)+C{{l}_{2}}(g)\] is 0.04 at \[250{}^\circ C\]. How many moles of \[PC{{l}_{5}}\] must be added to a 3 L flask to obtain a \[C{{l}_{2}}\] concentration of 0.15M

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