\[\int_{{}}^{{}}{x{{\tan }^{-1}}}xdx=\] [Roorkee 1979]

1.	\[\int_{{}}^{{}}{x{{\tan }^{-1}}}xdx=\] [Roorkee 1979]
A.	\[\frac{1}{2}({{x}^{2}}+1){{\tan }^{-1}}x-\frac{1}{2}x+c\]
B.	\[\frac{1}{2}({{x}^{2}}-1){{\tan }^{-1}}x-\frac{1}{2}x+c\]
C.	\[\frac{1}{2}({{x}^{2}}+1){{\tan }^{-1}}x+\frac{1}{2}x+c\]
D.	\[\frac{1}{2}({{x}^{2}}+1){{\tan }^{-1}}x-x+c\]
Answer» B. \[\frac{1}{2}({{x}^{2}}-1){{\tan }^{-1}}x-\frac{1}{2}x+c\]

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\[\int_{{}}^{{}}{x{{\tan }^{-1}}}xdx=\] [Roorkee 1979]

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