1.

\[\int_{{}}^{{}}{\text{cose}{{\text{c}}^{2}}x\ dx}\] is equal to [MP PET 1999]

A.            \[\cot x+c\]
B.            \[-\cot x+c\]
C.            \[{{\tan }^{2}}x+c\]
D.            \[-{{\cot }^{2}}x+c\]
Answer» C.            \[{{\tan }^{2}}x+c\]


Discussion

No Comment Found

Related MCQs