\[\int_{{}}^{{}}{{{\tan }^{3}}}2x\sec 2x\ dx=\] [IIT 1977]

1.	\[\int_{{}}^{{}}{{{\tan }^{3}}}2x\sec 2x\ dx=\] [IIT 1977]
A.	\[\frac{1}{6}{{\sec }^{3}}2x-\frac{1}{2}\sec 2x+c\]
B.	\[\frac{1}{6}{{\sec }^{3}}2x+\frac{1}{2}\sec 2x+c\]
C.	\[\frac{1}{9}{{\sec }^{2}}2x-\frac{1}{3}\sec 2x+c\]
D.	None of these
Answer» B. \[\frac{1}{6}{{\sec }^{3}}2x+\frac{1}{2}\sec 2x+c\]

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\[\int_{{}}^{{}}{{{\tan }^{3}}}2x\sec 2x\ dx=\] [IIT 1977]

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