1.

\[\int{\sqrt{{{x}^{2}}+{{a}^{2}}}\,\,dx}\] equals to                                                [RPET 2001]

A.            \[\frac{x}{2}\sqrt{{{x}^{2}}+{{a}^{2}}}\,-\frac{{{a}^{2}}}{2}\log \{x+\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\]
B.            \[\frac{x}{2}\sqrt{{{x}^{2}}+{{a}^{2}}}\,+\frac{{{a}^{2}}}{2}\log \,\{x+\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\]
C.            \[\frac{x}{2}\sqrt{{{x}^{2}}+{{a}^{2}}}\,-\frac{{{a}^{2}}}{2}\log \{x-\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\]
D.            \[\frac{x}{2}\sqrt{{{x}^{2}}+{{a}^{2}}}\,+\frac{{{a}^{2}}}{2}\log \{x-\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\]
Answer» C.            \[\frac{x}{2}\sqrt{{{x}^{2}}+{{a}^{2}}}\,-\frac{{{a}^{2}}}{2}\log \{x-\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\]


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