MCQOPTIONS
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| 1. |
\[\int{\sqrt{{{x}^{2}}+{{a}^{2}}}\,\,dx}\] equals to [RPET 2001] |
| A. | \[\frac{x}{2}\sqrt{{{x}^{2}}+{{a}^{2}}}\,-\frac{{{a}^{2}}}{2}\log \{x+\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\] |
| B. | \[\frac{x}{2}\sqrt{{{x}^{2}}+{{a}^{2}}}\,+\frac{{{a}^{2}}}{2}\log \,\{x+\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\] |
| C. | \[\frac{x}{2}\sqrt{{{x}^{2}}+{{a}^{2}}}\,-\frac{{{a}^{2}}}{2}\log \{x-\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\] |
| D. | \[\frac{x}{2}\sqrt{{{x}^{2}}+{{a}^{2}}}\,+\frac{{{a}^{2}}}{2}\log \{x-\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\] |
| Answer» C. \[\frac{x}{2}\sqrt{{{x}^{2}}+{{a}^{2}}}\,-\frac{{{a}^{2}}}{2}\log \{x-\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\] | |