\[\int{\sqrt{\frac{x}{1-x}}dx}\] is equal to

1.	\[\int{\sqrt{\frac{x}{1-x}}dx}\] is equal to
A.	\[{{\sin }^{-1}}\sqrt{x}+c\]
B.	\[{{\sin }^{-1}}\{\sqrt{x}-\sqrt{x(1-x)\}}+c\]
C.	\[{{\sin }^{-1}}\sqrt{x(1-x)}+c\]
D.	\[{{\sin }^{-1}}\sqrt{x}-\sqrt{x(1-x)}+c\]
Answer» E.

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\[\int{\sqrt{\frac{x}{1-x}}dx}\] is equal to

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