\[\int{\sqrt{\frac{1+x}{1-x}}\,\,dx=}\] [RPET 2002]

\[-{{\sin }^{-1}}x-\sqrt{{{x}^{2}}-1}\,+c\]

\[-{{\sin }^{-1}}x-\sqrt{1-{{x}^{2}}}\,+c\]

\[{{\sin }^{-1}}x+\sqrt{1-{{x}^{2}}}\,+c\]

\[{{\sin }^{-1}}x-\sqrt{1-{{x}^{2}}}\,+c\]

\[\int{\sqrt{\frac{1+x}{1-x}}\,\,dx=}\] �

1.	\[\int{\sqrt{\frac{1+x}{1-x}}\,\,dx=}\] [RPET 2002]
A.	\[-{{\sin }^{-1}}x-\sqrt{1-{{x}^{2}}}\,+c\]
B.	\[{{\sin }^{-1}}x+\sqrt{1-{{x}^{2}}}\,+c\]
C.	\[{{\sin }^{-1}}x-\sqrt{1-{{x}^{2}}}\,+c\]
D.	\[-{{\sin }^{-1}}x-\sqrt{{{x}^{2}}-1}\,+c\]
Answer» D. \[-{{\sin }^{-1}}x-\sqrt{{{x}^{2}}-1}\,+c\]

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\[\int{\sqrt{\frac{1+x}{1-x}}\,\,dx=}\] [RPET 2002]

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