\[\int_{{}}^{{}}{\sqrt{\frac{1-x}{1+x}}}\ dx=\] [IIT 1971]

\[{{\sin }^{-1}}x-\frac{1}{2}\sqrt{1-{{x}^{2}}}+c\]

\[{{\sin }^{-1}}x+\frac{1}{2}\sqrt{1-{{x}^{2}}}+c\]

\[{{\sin }^{-1}}x-\sqrt{1-{{x}^{2}}}+c\]

\[{{\sin }^{-1}}x+\sqrt{1-{{x}^{2}}}+c\]

\[\int_{{}}^{{}}{\sqrt{\frac{1-x}{1+x}}}\ dx=\] [IIT 197

1.	\[\int_{{}}^{{}}{\sqrt{\frac{1-x}{1+x}}}\ dx=\] [IIT 1971]
A.	\[{{\sin }^{-1}}x-\frac{1}{2}\sqrt{1-{{x}^{2}}}+c\]
B.	\[{{\sin }^{-1}}x+\frac{1}{2}\sqrt{1-{{x}^{2}}}+c\]
C.	\[{{\sin }^{-1}}x-\sqrt{1-{{x}^{2}}}+c\]
D.	\[{{\sin }^{-1}}x+\sqrt{1-{{x}^{2}}}+c\]
Answer» E.

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\[\int_{{}}^{{}}{\sqrt{\frac{1-x}{1+x}}}\ dx=\] [IIT 1971]

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