\[\int_{\pi /6}^{\pi /3}{\frac{dx}{1+\sqrt{\tan x}}=}\] [Kerala (Engg.) 2005]

\[\int_{\pi /6}^{\pi /3}{\frac{dx}{1+\sqrt{\tan x}}=}\] �

1.	\[\int_{\pi /6}^{\pi /3}{\frac{dx}{1+\sqrt{\tan x}}=}\] [Kerala (Engg.) 2005]
A.	\[\pi /12\]
B.	\[\pi /2\]
C.	\[\pi /6\]
D.	\[\pi /4\]
E.	\[2\pi /3\]
Answer» B. \[\pi /2\]

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\[\int_{\pi /6}^{\pi /3}{\frac{dx}{1+\sqrt{\tan x}}=}\] [Kerala (Engg.) 2005]

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