\[\int\limits_{0}^{\pi }{xf(\sin \,\,x)dx}\] is equal to

1.	\[\int\limits_{0}^{\pi }{xf(\sin \,\,x)dx}\] is equal to
A.	\[\pi \int\limits_{0}^{\pi }{f(cos\,\,x)dx}\]
B.	\[\pi \int\limits_{0}^{\pi }{f(sin\,\,x)dx}\]
C.	\[\frac{\pi }{2}\int\limits_{0}^{\pi /2}{f(sin\,\,x)dx}\]
D.	\[\pi \int\limits_{0}^{\pi /2}{f(cos\,\,x)dx}\]
Answer» E.

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\[\int\limits_{0}^{\pi }{xf(\sin \,\,x)dx}\] is equal to

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