1.

\[{{\int{\left\{ \frac{(\log x-1)}{1+{{(\log x)}^{2}}} \right\}}}^{2}}dx\] is equal to                 [AIEEE 2005]

A.                 \[\frac{x{{e}^{x}}}{1+{{x}^{2}}}+c\]
B.                 \[\frac{x}{{{(\log x)}^{2}}+1}+C\]
C.                 \[\frac{\log x}{{{(\log x)}^{2}}+1}+c\]
D.                 \[\frac{x}{{{x}^{2}}+1}+c\]
Answer» C.                 \[\frac{\log x}{{{(\log x)}^{2}}+1}+c\]


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