\[\int_{{}}^{{}}{\frac{x}{{{x}^{4}}-1}dx=}\]

1.	\[\int_{{}}^{{}}{\frac{x}{{{x}^{4}}-1}dx=}\]
A.	\[\frac{1}{4}\log \left[ \frac{{{x}^{2}}-1}{{{x}^{2}}+1} \right]+c\]
B.	\[\frac{1}{4}\log \left[ \frac{{{x}^{2}}+1}{{{x}^{2}}-1} \right]+c\]
C.	\[\frac{1}{2}\log \left[ \frac{{{x}^{2}}-1}{{{x}^{2}}+1} \right]+c\]
D.	\[\frac{1}{2}\log \left[ \frac{{{x}^{2}}+1}{{{x}^{2}}-1} \right]+c\]
Answer» B. \[\frac{1}{4}\log \left[ \frac{{{x}^{2}}+1}{{{x}^{2}}-1} \right]+c\]

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\[\int_{{}}^{{}}{\frac{x}{{{x}^{4}}-1}dx=}\]

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