\[\int_{{}}^{{}}{\frac{x{{\sin }^{-1}}x}{\sqrt{1-{{x}^{2}}}}\ }dx=\] [MNR 1978; EAMCET 1982; IIT 1984]

\[x+\sqrt{1-{{x}^{2}}}{{\sin }^{-1}}x+c\]

\[x-\sqrt{1-{{x}^{2}}}{{\sin }^{-1}}x+c\]

\[\sqrt{1-{{x}^{2}}}{{\sin }^{-1}}x-x+c\]

\[\int_{{}}^{{}}{\frac{x{{\sin }^{-1}}x}{\sqrt{1-{{x}^{2}}}}\ }dx=\] �

1.	\[\int_{{}}^{{}}{\frac{x{{\sin }^{-1}}x}{\sqrt{1-{{x}^{2}}}}\ }dx=\] [MNR 1978; EAMCET 1982; IIT 1984]
A.	\[x-\sqrt{1-{{x}^{2}}}{{\sin }^{-1}}x+c\]
B.	\[x+\sqrt{1-{{x}^{2}}}{{\sin }^{-1}}x+c\]
C.	\[\sqrt{1-{{x}^{2}}}{{\sin }^{-1}}x-x+c\]
D.	None of these
Answer» B. \[x+\sqrt{1-{{x}^{2}}}{{\sin }^{-1}}x+c\]

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\[\int_{{}}^{{}}{\frac{x{{\sin }^{-1}}x}{\sqrt{1-{{x}^{2}}}}\ }dx=\] [MNR 1978; EAMCET 1982; IIT 1984]

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