1.

\[\int_{{}}^{{}}{\frac{x{{e}^{x}}}{{{(1+x)}^{2}}}dx=}\] [MP PET 1997; UPSEAT 2001; RPET 2002]

A.                 \[\frac{{{e}^{-x}}}{1+x}+c\]
B.                 \[-\frac{{{e}^{-x}}}{1+x}+c\]
C.                 \[\frac{{{e}^{x}}}{1+x}+c\]
D.                 \[-\frac{{{e}^{x}}}{1+x}+c\]
Answer» D.                 \[-\frac{{{e}^{x}}}{1+x}+c\]


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