1.

\[\int_{{}}^{{}}{\frac{{{x}^{2}}+1}{x({{x}^{2}}-1)}\ dx}\] is equal to            [MP PET 1999]

A.            \[\log \frac{{{x}^{2}}-1}{x}+c\]
B.            \[-\log \frac{{{x}^{2}}-1}{x}+c\]
C.            \[\log \frac{x}{{{x}^{2}}+1}+c\]
D.            \[-\log \frac{x}{{{x}^{2}}+1}+c\]
Answer» B.            \[-\log \frac{{{x}^{2}}-1}{x}+c\]


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