\[\int{\frac{({{x}^{2}}-1)}{x\sqrt{{{x}^{4}}+3{{x}^{2}}+1}}dx}\] is equal to

\[\log \left| x-\frac{1}{x}+\sqrt{{{x}^{2}}+\frac{1}{{{x}^{2}}}-3} \right|+C\]

\[\log \left| x+\frac{1}{x}+\sqrt{{{x}^{2}}+\frac{1}{{{x}^{2}}}+3} \right|+C\]

\[\log \left| x+\sqrt{{{x}^{2}}+3} \right|+C\]

\[\int{\frac{({{x}^{2}}-1)}{x\sqrt{{{x}^{4}}+3{{x}^{2}}+1}}dx}\] is eq

1.	\[\int{\frac{({{x}^{2}}-1)}{x\sqrt{{{x}^{4}}+3{{x}^{2}}+1}}dx}\] is equal to
A.	\[\log \left\| x+\frac{1}{x}+\sqrt{{{x}^{2}}+\frac{1}{{{x}^{2}}}+3} \right\|+C\]
B.	\[\log \left\| x-\frac{1}{x}+\sqrt{{{x}^{2}}+\frac{1}{{{x}^{2}}}-3} \right\|+C\]
C.	\[\log \left\| x+\sqrt{{{x}^{2}}+3} \right\|+C\]
D.	None of these
Answer» B. \[\log \left\| x-\frac{1}{x}+\sqrt{{{x}^{2}}+\frac{1}{{{x}^{2}}}-3} \right\|+C\]

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\[\int{\frac{({{x}^{2}}-1)}{x\sqrt{{{x}^{4}}+3{{x}^{2}}+1}}dx}\] is equal to

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