\[\int_{{}}^{{}}{\frac{x-1}{{{(x+1)}^{2}}}\ dx=}\]

1.	\[\int_{{}}^{{}}{\frac{x-1}{{{(x+1)}^{2}}}\ dx=}\]
A.	\[\log (x+1)+\frac{2}{x+1}+c\]
B.	\[\log (x+1)-\frac{2}{x+1}+c\]
C.	\[\frac{2}{x+1}-\log (x+1)+c\]
D.	None of these
Answer» B. \[\log (x+1)-\frac{2}{x+1}+c\]

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\[\int_{{}}^{{}}{\frac{x-1}{{{(x+1)}^{2}}}\ dx=}\]

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