1.

\[\int_{{}}^{{}}{\frac{t}{{{e}^{3{{t}^{2}}}}}\ dt=}\] [MP PET 1997]

A.            \[\frac{1}{6}{{e}^{3{{t}^{2}}}}+c\]
B.            \[-\frac{1}{6}{{e}^{3{{t}^{2}}}}+c\]
C.            \[\frac{1}{6}{{e}^{-3{{t}^{2}}}}+c\]
D.            \[-\frac{1}{6}{{e}^{-3{{t}^{2}}}}+c\]
Answer» E.


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