\[\int_{{}}^{{}}{\frac{\sqrt{x}}{1+x}dx=}\]

1.	\[\int_{{}}^{{}}{\frac{\sqrt{x}}{1+x}dx=}\]
A.	\[\sqrt{x}-{{\tan }^{-1}}\sqrt{x}+c\]
B.	\[2(\sqrt{x}-{{\tan }^{-1}}\sqrt{x})+c\]
C.	\[2(\sqrt{x}+{{\tan }^{-1}}x)+c\]
D.	\[\sqrt{1+x}+c\]
Answer» C. \[2(\sqrt{x}+{{\tan }^{-1}}x)+c\]

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\[\int_{{}}^{{}}{\frac{\sqrt{x}}{1+x}dx=}\]

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