1.

\[\int_{{}}^{{}}{\frac{\sin x}{\sin x-\cos x}}\ dx=\]           [Roorkee 1988]

A.            \[\frac{1}{2}\log (\sin x-\cos x)+x+c\]                           
B.            \[\frac{1}{2}[\log (\sin x-\cos x)+x]+c\]
C.            \[\frac{1}{2}\log (\cos x-\sin x)+x+c\]                           
D.            \[\frac{1}{2}[\log (\cos x-\sin x)+x]+c\]
Answer» C.            \[\frac{1}{2}\log (\cos x-\sin x)+x+c\]                           


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