\[\int \frac{{{\sin }^{8}}x-{{\cos }^{8}}x}{1-2{{\sin }^{2}}x{{\cos }^{2}}x}dx\] is equal to

\[\int \frac{{{\sin }^{8}}x-{{\cos }^{8}}x}{1-2{{\sin }^{2}}x{{\cos }^

1.	\[\int \frac{{{\sin }^{8}}x-{{\cos }^{8}}x}{1-2{{\sin }^{2}}x{{\cos }^{2}}x}dx\] is equal to
A.	\[\frac{1}{2}\sin 2x+C\]
B.	\[-\frac{1}{2}\sin 2x+C\]
C.	\[-\frac{1}{2}\sin x+C\]
D.	\[-{{\sin }^{2}}x+C\]
Answer» C. \[-\frac{1}{2}\sin x+C\]

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\[\int \frac{{{\sin }^{8}}x-{{\cos }^{8}}x}{1-2{{\sin }^{2}}x{{\cos }^{2}}x}dx\] is equal to

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