\[\int_{{}}^{{}}{\frac{{{\sin }^{8}}x-{{\cos }^{8}}x}{1-2{{\sin }^{2}}x{{\cos }^{2}}x}\ dx=}\] [IIT 1986]

\[\int_{{}}^{{}}{\frac{{{\sin }^{8}}x-{{\cos }^{8}}x}{1-2{{\sin }^{2}}

1.	\[\int_{{}}^{{}}{\frac{{{\sin }^{8}}x-{{\cos }^{8}}x}{1-2{{\sin }^{2}}x{{\cos }^{2}}x}\ dx=}\] [IIT 1986]
A.	\[\sin 2x+c\]
B.	\[-\frac{1}{2}\sin 2x+c\]
C.	\[\frac{1}{2}\sin 2x+c\]
D.	\[-\sin 2x+c\]
Answer» C. \[\frac{1}{2}\sin 2x+c\]

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\[\int_{{}}^{{}}{\frac{{{\sin }^{8}}x-{{\cos }^{8}}x}{1-2{{\sin }^{2}}x{{\cos }^{2}}x}\ dx=}\] [IIT 1986]

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