\[\int_{{}}^{{}}{\frac{\sin 2xdx}{1+{{\cos }^{2}}x}}=\] [Karnataka CET 2005]

\[\frac{1}{2}\log (1+{{\cos }^{2}}x)+c\]

\[\frac{1}{2}\log (1+\cos 2x)+c\]

\[\int_{{}}^{{}}{\frac{\sin 2xdx}{1+{{\cos }^{2}}x}}=\] [Kar

1.	\[\int_{{}}^{{}}{\frac{\sin 2xdx}{1+{{\cos }^{2}}x}}=\] [Karnataka CET 2005]
A.	\[\frac{1}{2}\log (1+{{\cos }^{2}}x)+c\]
B.	\[2\log (1+{{\cos }^{2}}x)+c\]
C.	\[\frac{1}{2}\log (1+\cos 2x)+c\]
D.	\[-\log (1+{{\cos }^{2}}x)+c\]
Answer» E.

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\[\int_{{}}^{{}}{\frac{\sin 2xdx}{1+{{\cos }^{2}}x}}=\] [Karnataka CET 2005]

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