\[\int_{{}}^{{}}{\frac{\sin 2x}{1+{{\sin }^{2}}x}dx=}\] [Roorkee 1976]

\[\frac{1}{2}\log (1+{{\sin }^{2}}x)+c\]

\[\int_{{}}^{{}}{\frac{\sin 2x}{1+{{\sin }^{2}}x}dx=}\] [Roork

1.	\[\int_{{}}^{{}}{\frac{\sin 2x}{1+{{\sin }^{2}}x}dx=}\] [Roorkee 1976]
A.	\[\log \sin 2x+c\]
B.	\[\log (1+{{\sin }^{2}}x)+c\]
C.	\[\frac{1}{2}\log (1+{{\sin }^{2}}x)+c\]
D.	\[{{\tan }^{-1}}(\sin x)+c\]
Answer» C. \[\frac{1}{2}\log (1+{{\sin }^{2}}x)+c\]

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\[\int_{{}}^{{}}{\frac{\sin 2x}{1+{{\sin }^{2}}x}dx=}\] [Roorkee 1976]

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