\[\int_{{}}^{{}}{\frac{{{\sec }^{2}}x}{1+\tan x}\ dx=}\] [MP PET 1987]

\[-\frac{1}{{{(1+\tan x)}^{2}}}+c\]

\[\int_{{}}^{{}}{\frac{{{\sec }^{2}}x}{1+\tan x}\ dx=}\] [MP PET

1.	\[\int_{{}}^{{}}{\frac{{{\sec }^{2}}x}{1+\tan x}\ dx=}\] [MP PET 1987]
A.	\[\log (\cos x+\sin x)+c\]
B.	\[\log ({{\sec }^{2}}x)+c\]
C.	\[\log (1+\tan x)+c\]
D.	\[-\frac{1}{{{(1+\tan x)}^{2}}}+c\]
Answer» D. \[-\frac{1}{{{(1+\tan x)}^{2}}}+c\]

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\[\int_{{}}^{{}}{\frac{{{\sec }^{2}}x}{1+\tan x}\ dx=}\] [MP PET 1987]

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