\[\int{\frac{\{f(x).\phi '(x)-f'(x).\phi (x)\}}{f(x).\phi (x)}}\log \frac{f(x)}{\phi (x)}dx\] is equal to:

\[\frac{\phi (x)}{f(x)}\log \frac{\phi (x)}{f(x)}+k\]

\[\log \frac{\phi (x)}{f(x)}+k\]

\[\frac{1}{2}{{\left\{ \log \frac{\phi (x)}{f(x)} \right\}}^{2}}+k\]

\[\int{\frac{\{f(x).\phi '(x)-f'(x).\phi (x)\}}{f(x).\phi (x)}}\log \f

1.	\[\int{\frac{\{f(x).\phi '(x)-f'(x).\phi (x)\}}{f(x).\phi (x)}}\log \frac{f(x)}{\phi (x)}dx\] is equal to:
A.	\[\log \frac{\phi (x)}{f(x)}+k\]
B.	\[\frac{1}{2}{{\left\{ \log \frac{\phi (x)}{f(x)} \right\}}^{2}}+k\]
C.	\[\frac{\phi (x)}{f(x)}\log \frac{\phi (x)}{f(x)}+k\]
D.	None of these
Answer» C. \[\frac{\phi (x)}{f(x)}\log \frac{\phi (x)}{f(x)}+k\]

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\[\int{\frac{\{f(x).\phi '(x)-f'(x).\phi (x)\}}{f(x).\phi (x)}}\log \frac{f(x)}{\phi (x)}dx\] is equal to:

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