\[\int_{{}}^{{}}{\frac{{{e}^{x}}(x-1)}{{{x}^{2}}}\ dx=}\]

1.	\[\int_{{}}^{{}}{\frac{{{e}^{x}}(x-1)}{{{x}^{2}}}\ dx=}\]
A.	\[\frac{1}{x}{{e}^{x}}+c\]
B.	\[x{{e}^{-x}}+c\]
C.	\[\frac{1}{{{x}^{2}}}{{e}^{x}}+c\]
D.	\[\left( x-\frac{1}{x} \right){{e}^{x}}+c\]
Answer» B. \[x{{e}^{-x}}+c\]

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\[\int_{{}}^{{}}{\frac{{{e}^{x}}(x-1)}{{{x}^{2}}}\ dx=}\]

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