\[\int_{{}}^{{}}{\frac{{{e}^{x}}\ dx}{\sqrt{1-{{e}^{2x}}}}=}\]

1.	\[\int_{{}}^{{}}{\frac{{{e}^{x}}\ dx}{\sqrt{1-{{e}^{2x}}}}=}\]
A.	\[{{\cos }^{-1}}({{e}^{x}})+c\]
B.	\[-{{\cos }^{-1}}({{e}^{x}})+c\]
C.	\[{{\cos }^{-1}}({{e}^{2x}})+c\]
D.	\[\sqrt{1-{{e}^{2x}}}+c\]
Answer» C. \[{{\cos }^{-1}}({{e}^{2x}})+c\]

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\[\int_{{}}^{{}}{\frac{{{e}^{x}}\ dx}{\sqrt{1-{{e}^{2x}}}}=}\]

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