\[\int_{{}}^{{}}{\frac{{{e}^{-x}}}{1+{{e}^{x}}}\ dx=}\]

1.	\[\int_{{}}^{{}}{\frac{{{e}^{-x}}}{1+{{e}^{x}}}\ dx=}\]
A.	\[\log (1+{{e}^{x}})-x-{{e}^{-x}}+c\]
B.	\[\log (1+{{e}^{x}})+x-{{e}^{-x}}+c\]
C.	\[\log (1+{{e}^{x}})-x+{{e}^{-x}}+c\]
D.	\[\log (1+{{e}^{x}})+x+{{e}^{-x}}+c\]
Answer» B. \[\log (1+{{e}^{x}})+x-{{e}^{-x}}+c\]

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\[\int_{{}}^{{}}{\frac{{{e}^{-x}}}{1+{{e}^{x}}}\ dx=}\]

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