1.

\[\int_{{}}^{{}}{\frac{{{e}^{2x}}-1}{{{e}^{2x}}+1}}\ dx=\] [MP PET 1987]

A.            \[\frac{{{e}^{2x}}-1}{{{e}^{2x}}+1}+c\]
B.            \[\log ({{e}^{2x}}+1)-x+c\]
C.            \[\log ({{e}^{2x}}+1)+c\]
D.            None of these
Answer» C.            \[\log ({{e}^{2x}}+1)+c\]


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