\[\int_{{}}^{{}}{\frac{{{e}^{2x}}+1}{{{e}^{2x}}-1}\ dx}\] equals [RPET 1996]

\[\log ({{e}^{x}}+{{e}^{-x}})+c\]

\[\log ({{e}^{x}}-{{e}^{-x}})+c\]

\[\log ({{e}^{-x}}-{{e}^{x}})+c\]

\[\int_{{}}^{{}}{\frac{{{e}^{2x}}+1}{{{e}^{2x}}-1}\ dx}\] equals

1.	\[\int_{{}}^{{}}{\frac{{{e}^{2x}}+1}{{{e}^{2x}}-1}\ dx}\] equals [RPET 1996]
A.	\[\log ({{e}^{x}}-{{e}^{-x}})+c\]
B.	\[\log ({{e}^{x}}+{{e}^{-x}})+c\]
C.	\[\log ({{e}^{-x}}-{{e}^{x}})+c\]
D.	\[\log (1-{{e}^{-x}})+c\]
Answer» B. \[\log ({{e}^{x}}+{{e}^{-x}})+c\]

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\[\int_{{}}^{{}}{\frac{{{e}^{2x}}+1}{{{e}^{2x}}-1}\ dx}\] equals [RPET 1996]

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