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\[\int_{{}}^{{}}{\frac{dx}{{{e}^{x}}+{{e}^{-x}}}=}\] [Bihar CEE 1976; MNR 1974]

A.            \[{{\tan }^{-1}}({{e}^{-x}})\]
B.            \[{{\tan }^{-1}}({{e}^{x}})\]
C.            \[\log ({{e}^{x}}-{{e}^{-x}})\]
D.            \[\log ({{e}^{x}}+{{e}^{-x}})\]
Answer» C.            \[\log ({{e}^{x}}-{{e}^{-x}})\]


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